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Proof step 1 from proof ex-fits-validrefs (
previous step
)
¬ junkref(str, r, st), fits(r, sks, st) ⊦ ∃ refs. validrefs(str, r ' + refs, st[r -- _type] .type, st) ∧ # refs = # sks ∧ (∀ sks0. sks0 ⊑ sks ∧ sks0 ≠ [] → st[r -- sks0] .refval = (r ' + refs)[# sks0])
Lemma
ex-fits-validrefs-stronger