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Proof step 12 from proof ex-fits-validrefs (previous step)

∃ refs. validrefs(str, r ' + refs, st[r -- _type] .type, st) ∧ # refs = # sks ∧ (∀ sks0. sks0 ⊑ sks ∧ sks0 ≠ [] → st[r -- sks0] .refval = (r ' + refs)[# sks0]), fits(r, sks, st) ⊦ junkref(str, r, st), ∃ refs. validrefs(str, r ' + refs, st[r -- _type] .type, st) ∧ st[r -- sks] .refval = (r ' + refs) .last

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
# refs = # sks, fits(r, sks, st), validrefs(str, r ' + refs, st[r -- _type] .type, st), ∀ sks0. sks0 ⊑ sks ∧ sks0 ≠ [] → st[r -- sks0] .refval = (r ' + refs)[# sks0] ⊦ junkref(str, r, st), ∃ refs. validrefs(str, r ' + refs, st[r -- _type] .type, st) ∧ st[r -- sks] .refval = (r ' + refs) .last

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]