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Proof step 7 from proof ex-fits-validrefs (previous step)

# refs = # sks, fits(r, sks, st), validrefs(str, r ' + refs, st[r -- _type] .type, st), sks ≠ [] → st[r -- sks] .refval = (r ' + refs)[# sks] ⊦ st[r -- sks] .refval = (r ' + refs) .last, junkref(str, r, st)

User applied rule cut formula

And obtained the following new goals

Proof step 5:
sks ≠ [], # refs = # sks, fits(r, sks, st), validrefs(str, r ' + refs, st[r -- _type] .type, st), sks ≠ [] → st[r -- sks] .refval = (r ' + refs)[# sks] ⊦ st[r -- sks] .refval = (r ' + refs) .last, junkref(str, r, st)
Proof step 6:
⊦ fits(r, [], st)

Rule argument

[fma-arg: sks ≠ []]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ # [] = 0], [CSIMPSEQ : ⊦ # refs = 0 ↔ refs = []], [CSIMPSEQ : ⊦ st[r -- []] = refval(r)], [CSIMPSEQ : ⊦ refval(r) .refval = r], [CSIMPSEQ : ⊦ refs + [] = refs], [CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ r ' .last = r])], [EXTRAFMAS : (sks ≠ [])]]