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Proof step 12 from proof ex-validrefs-fits (previous step)

refs = r + refs0, validrefs(str, refs, ty, st) ⊦ refs = [], ∃ sks. fits(r, sks, st) ∧ st[r -- sks] .refval = refs .last

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
validrefs(str, r ' + refs0, ty, st) ⊦ ∃ sks. fits(r, sks, st) ∧ st[r -- sks] .refval = (r ' + refs0) .last

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ r ' + refs ≠ []], [CSIMPSEQ : ⊦ r + refs = r ' + refs])]]