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Proof step 7 from proof ex-validrefs-fits (previous step)

# sks = # refs0, validrefs(str, r ' + refs0, ty, st), fits(r, sks, st), ∀ n. n ≠ 0 ∧ ¬ # refs0 < n → st[r -- firstn(n, sks)] .refval = (r ' + refs0)[n] ⊦ st[r -- sks] .refval = (r ' + refs0) .last

User applied rule all left

And obtained the following new goals

Proof step 6:
# sks = # refs0, validrefs(str, r ' + refs0, ty, st), fits(r, sks, st), # refs0 ≠ 0 ∧ ¬ # refs0 < # refs0 → st[r -- firstn(# refs0, sks)] .refval = (r ' + refs0)[# refs0] ⊦ st[r -- sks] .refval = (r ' + refs0) .last

Rule argument

[EXRARG : pos: left 4, [extquanttermlist: (# refs0)abort:F, discard:T, computed:T]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (# refs0)]]