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Proof step 9 from proof ex-validrefs-fits (previous step)

# sks = # refs0, validrefs(str, r ' + refs0, ty, st), fits(r, sks, st), ∀ n. n ≠ 0 ∧ ¬ # refs0 < n → st[r -- firstn(n, sks)] .refval = (r ' + refs0)[n] ⊦ ∃ sks. fits(r, sks, st) ∧ st[r -- sks] .refval = (r ' + refs0) .last

User applied rule exists right

And obtained the following new goals

Proof step 8:
# sks = # refs0, validrefs(str, r ' + refs0, ty, st), fits(r, sks, st), ∀ n. n ≠ 0 ∧ ¬ # refs0 < n → st[r -- firstn(n, sks)] .refval = (r ' + refs0)[n] ⊦ fits(r, sks, st) ∧ st[r -- sks] .refval = (r ' + refs0) .last

Rule argument

[EXRARG : pos: right 1, [extquanttermlist: (sks)abort:F, discard:T, computed:T]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (sks)]]