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Proof step 41 from proof fits-in (previous step)

is_referencevalue(st[r -- sk]), fits(st[r -- sk] .refval, sks0, st), r -- sk ∈ st, r ∈ st, is_classtype(st[r -- _type] .type) → sk ∈ instfields(st[r -- _type] .type .class), is_arraytype(st[r -- _type] .type) → is_indexkey(sk) ∧ 0 ≤ sk .index ∧ sk .index < st[r -- _length] .intval, ∀ str0, r0, st0. ¬ junkref(str0, r0, st0) ∧ fits(r0, sks0, st0) → r0 -- sks0 ∈ st0 ⊦ sks0 = [], r = jvmref, junkref(str, r, st), st[r -- sk] .refval -- sks0 ∈ st

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 40:
st[r -- sk] = refval(r1), is_referencevalue(st[r -- sk]), fits(r1, sks0, st), r -- sk ∈ st, r ∈ st, is_classtype(st[r -- _type] .type) → sk ∈ instfields(st[r -- _type] .type .class), is_arraytype(st[r -- _type] .type) → is_indexkey(sk) ∧ 0 ≤ sk .index ∧ sk .index < st[r -- _length] .intval, ∀ str0, r0, st0. ¬ junkref(str0, r0, st0) ∧ fits(r0, sks0, st0) → r0 -- sks0 ∈ st0 ⊦ sks0 = [], r = jvmref, junkref(str, r, st), r1 -- sks0 ∈ st

Rule argument

[speclemmaarg: ,is_referencevalue(val) → (r = val .refval ↔ val = refval(r)) ,[val, r] → [st[r -- sk], r1] ,T ,javavalue , ,elim-13 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_referencevalue(val) → ( r = val .refval ↔ val = refval(r))])], [EXTRATERMS : (st[r -- sk], r1)]]