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Proof step 19 from proof fits-no-refval (previous step)

is_array(str, r, st), st[r -- i '] = refval(r0), is_array(str, r, st), junkref(str, r0, st), sks1 ⊑ sks, fits(r0, sks + sk ', st), is_arraytype(st[r -- _type] .type), i < st[r -- _length] .intval, 0 < st[r -- _length] .intval, 0 ≤ i, ∀ sks0, r, sk, st, str. sks0 ⊑ sks ∧ fits(r, sks + sk ', st) → is_referencevalue(st[r -- sks0]) ∨ junkref(str, r, st) ⊦ r = jvmref, ∃ i. 0 ≤ i ∧ i < st[r -- _length] .intval ∧ is_referencevalue(st[r -- i ']) ∧ st[r -- i '] .refval ≠ jvmref ∧ (¬ st[st[r -- i '] .refval -- _type] .type ≤ st[r -- _type] .type .type ∨ junkref(str, st[r -- i '] .refval, st)), is_referencevalue(st[r -- (i ' ' + sks1)])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
st[r -- i '] = refval(r0), is_array(str, r, st), junkref(str, r0, st), sks1 ⊑ sks, fits(r0, sks + sk ', st), is_arraytype(st[r -- _type] .type), i < st[r -- _length] .intval, 0 < st[r -- _length] .intval, 0 ≤ i, ∀ sks0, r, sk, st, str. sks0 ⊑ sks ∧ fits(r, sks + sk ', st) → is_referencevalue(st[r -- sks0]) ∨ junkref(str, r, st) ⊦ r = jvmref, is_referencevalue(st[r -- (i ' ' + sks1)]), ∃ i0. ¬ i0 < 0 ∧ ¬ st[r -- _length] .intval ≤ i0 ∧ is_referencevalue(st[r -- i0 ']) ∧ st[r -- i0 '] .refval ≠ jvmref ∧ (¬ st[st[r -- i0 '] .refval -- _type] .type ≤ st[r -- _type] .type .type ∨ junkref(str, st[r -- i0 '] .refval, st))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : int-abs, , lels, ⊦ ¬ i < j ↔ j ≤ i], [CSIMPNAMEDSEQ : int-abs, , lels-01, ⊦ ¬ i ≤ j ↔ j < i])]]