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Proof step 27 from proof fits-no-refval (previous step)

st[r -- sk0] = refval(r0), junkref(str, r0, st), sks1 ⊑ sks, fits(r0, sks + sk ', st), is_classtype(st[r -- _type] .type) → sk0 ∈ instfields(st[r -- _type] .type .class), is_arraytype(st[r -- _type] .type) → is_indexkey(sk0) ∧ 0 ≤ sk0 .index ∧ sk0 .index < st[r -- _length] .intval, ∀ sks0, r, sk, st, str. sks0 ⊑ sks ∧ fits(r, sks + sk ', st) → is_referencevalue(st[r -- sks0]) ∨ junkref(str, r, st) ⊦ r = jvmref, junkref(str, r, st), is_referencevalue(st[r -- (sk0 ' + sks1)])

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

[x0lemmaarg: spec-name: junkrefs instance-name: lemma-name: junkref-is-junk antecedent: succedent: r ≠ jvmref ∧ ¬ is_valid_ref(str, r, st) → junkref(str, r, st) substlist: [st, r, str] → [st, r, str] add preconditions?: F is rewrite lemma?: T current spec?: F rotate lemma?: F replace all?: T paths: ((1, 0, 1)) dummy: () ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, r, str)]]