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Proof step 35 from proof fits-no-refval (previous step)

sks0 = sk0 + sks1, st[r -- sk0] = refval(r0), sks1 ⊑ sks, fits(r0, sks + sk ', st), is_classtype(st[r -- _type] .type) → sk0 ∈ instfields(st[r -- _type] .type .class), is_arraytype(st[r -- _type] .type) → is_indexkey(sk0) ∧ 0 ≤ sk0 .index ∧ sk0 .index < st[r -- _length] .intval, ∀ sks0, r, sk, st, str. sks0 ⊑ sks ∧ fits(r, sks + sk ', st) → is_referencevalue(st[r -- sks0]) ∨ junkref(str, r, st) ⊦ r = jvmref, sks0 = [], is_referencevalue(st[r -- sks0]), junkref(str, r, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 34:
st[r -- sk0] = refval(r0), sks1 ⊑ sks, fits(r0, sks + sk ', st), is_classtype(st[r -- _type] .type) → sk0 ∈ instfields(st[r -- _type] .type .class), is_arraytype(st[r -- _type] .type) → is_indexkey(sk0) ∧ 0 ≤ sk0 .index ∧ sk0 .index < st[r -- _length] .intval, ∀ sks0, r, sk, st, str. sks0 ⊑ sks ∧ fits(r, sks + sk ', st) → is_referencevalue(st[r -- sks0]) ∨ junkref(str, r, st) ⊦ r = jvmref, junkref(str, r, st), is_referencevalue(st[r -- (sk0 ' + sks1)])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : list, storekeys, a, ⊦ (sks + sks0) + sks1 = sks + sks0 + sks1], [CSIMPNAMEDSEQ : list, storekeys, e-01, ⊦ sk ' + sks ≠ []], [CSIMPNAMEDSEQ : list, storekeys, c, ⊦ sk + sks = sk ' + sks])]]