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Proof step 45 from proof fits-no-refval (previous step)

sks = sks1 + sk ', sks0 ⊑ sks1, fits(r, sks, st) ⊦ sks = [], is_referencevalue(st[r -- sks0]), junkref(str, r, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 44:
sks0 ⊑ sks1, fits(r, sks1 + sk ', st) ⊦ is_referencevalue(st[r -- sks0]), junkref(str, r, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : list, storekeys, a, ⊦ (sks + sks0) + sks1 = sks + sks0 + sks1], [CSIMPNAMEDSEQ : list, storekeys, e-02, ⊦ sks + sk ' ≠ []])]]