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Proof step 4 from proof fits-null (previous step)

∀ st. fits(jvmref, sks0, st) → sks0 = [], fits(jvmref, sk + sks0, st) ⊦ sk + sks0 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
fits(jvmref, sk ' + sks0, st), (∃ st. fits(jvmref, sks0, st)) → sks0 = [] ⊦

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (sks + sks0) + sks1 = sks + sks0 + sks1], [CSIMPSEQ : ⊦ sk ' + sks ≠ []], [CSIMPSEQ : ⊦ sk + sks = sk ' + sks])]]