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Proof step 6 from proof fits-pathex (previous step)

∃ refs. validrefs(str, r ' + refs, st[r -- _type] .type, st) ∧ st[r -- sks] .refval = (r ' + refs) .last, fits(r, sks, st) ⊦ junkref(str, r, st), path∃(str, r, st[r -- sks] .refval, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
st[r -- sks] .refval = (r ' + refs) .last, validrefs(str, r ' + refs, st[r -- _type] .type, st), fits(r, sks, st) ⊦ junkref(str, r, st), path∃(str, r, (r ' + refs) .last, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]