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Proof step 10 from proof fits-put-05-stronger (previous step)

¬ r -- _type ≠ r1 -- fs ', (st[r1 -- fs ', byteval(by)][r -- sk]) = refval(r0), is_bytevalue(st[r1 -- fs ']), fits(r0, sks0, st[r1 -- fs ', byteval(by)]), is_valid_ref(str, r, st), is_classtype((st[r1 -- fs ', byteval(by)][r -- _type]) .type) → sk ∈ instfields((st[r1 -- fs ', byteval(by)][r -- _type]) .type .class), is_arraytype((st[r1 -- fs ', byteval(by)][r -- _type]) .type) → is_indexkey(sk) ∧ 0 ≤ sk .index ∧ sk .index < (st[r1 -- fs ', byteval(by)][r -- _length]) .intval, ∀ r, st, r1, fs, by, str. fits(r, sks0, st[r1 -- fs ', byteval(by)]) ∧ is_bytevalue(st[r1 -- fs ']) → junkref(str, r, st) ∨ fits(r, sks0, st) ⊦ r = jvmref, junkref(str, r, st), is_referencevalue(st[r -- sk]) ∧ (is_classtype(st[r -- _type] .type) → sk ∈ instfields(st[r -- _type] .type .class)) ∧ (is_arraytype(st[r -- _type] .type) → ¬ is_fskey(sk) ∧ ¬ sk .index < 0 ∧ ¬ st[r -- _length] .intval ≤ sk .index) ∧ fits(st[r -- sk] .refval, sks0, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
_type = fs ', (st[r1 -- _type, byteval(by)][r1 -- sk]) = refval(r0), is_valid_ref(str, r1, st), fits(r0, sks0, st[r1 -- _type, byteval(by)]), is_bytevalue(st[r1 -- _type]), ∀ r, st, r1, fs, by, str. fits(r, sks0, st[r1 -- fs ', byteval(by)]) ∧ is_bytevalue(st[r1 -- fs ']) → junkref(str, r, st) ∨ fits(r, sks0, st), is_arraytype(byteval(by) .type) → is_indexkey(sk) ∧ 0 ≤ sk .index ∧ sk .index < (st[r1 -- _type, byteval(by)][r1 -- _length]) .intval, is_classtype(byteval(by) .type) → sk ∈ instfields(byteval(by) .type .class) ⊦ r1 = jvmref, junkref(str, r1, st), is_referencevalue(st[r1 -- sk]) ∧ (is_classtype(st[r1 -- _type] .type) → sk ∈ instfields(st[r1 -- _type] .type .class)) ∧ (is_arraytype(st[r1 -- _type] .type) → ¬ is_fskey(sk) ∧ ¬ sk .index < 0 ∧ ¬ st[r1 -- _length] .intval ≤ sk .index) ∧ fits(st[r1 -- sk] .refval, sks0, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (st[rk, val][rk]) = val], [CSIMPSEQ : ⊦ r -- sk = r0 -- sk0 ↔ r = r0 ∧ sk = sk0])]]