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Proof step 20 from proof fits-put-other (previous step)

st[r -- sk0] = refval(r1), ∀ sks3. sks3 + sk ' ⊑ sks → st[r1 -- sks3] .refval ≠ st[r1 -- sks] .refval, is_classtype(st[r -- _type] .type) → sk0 ∈ instfields(st[r -- _type] .type .class), r ≠ st[r1 -- sks] .refval ∨ sk0 ≠ sk ⊦ r = jvmref, sk = _length, sk = _type, (is_arraytype(st[r -- _type] .type) → is_indexkey(sk0) ∧ 0 ≤ sk0 .index ∧ sk0 .index < st[r -- _length] .intval) ∧ fits(r1, sks + sk ' + sks1, st[st[r1 -- sks] .refval -- sk, val]) ↔ (is_arraytype(st[r -- _type] .type) → ¬ is_fskey(sk0) ∧ ¬ sk0 .index < 0 ∧ ¬ st[r -- _length] .intval ≤ sk0 .index) ∧ fits(r1, sks + sk ' + sks1, st), fits(r1, sks + sk ' + sks1, st[st[r1 -- sks] .refval -- sk, val]) ↔ fits(r1, sks + sk ' + sks1, st), sk0 ' + sks + sk ' + sks1 = (sk0 ' + sks) + sk ' + sks1 ∧ st[r -- (sk0 ' + sks)] .refval = st[r1 -- sks] .refval ∧ (∀ sks3. sks3 + sk ' ⊑ sk0 ' + sks → st[r -- sks3] .refval ≠ st[r -- (sk0 ' + sks)] .refval)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : list, storekeys, a, ⊦ (sks + sks0) + sks1 = sks + sks0 + sks1])]]