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Proof step 52 from proof fits-put-short (previous step)

sks0 ≠ [], is_shortvalue(st[r1 -- fs ']), fits(r, sk ' + sks0, st), ∀ st, r1, fs, r, val, str. is_shortvalue(st[r1 -- fs ']) ∧ fits(r, sks0, st) → (st[r1 -- fs ', val][r -- sks0]) = st[r -- sks0] ∨ junkref(str, r, st) ⊦ (st[r1 -- fs ', val][(st[r1 -- fs ', val][r -- sk]) .refval -- sks0]) = st[r -- (sk ' + sks0)], junkref(str, r, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 51:
fits(r, sk ' + sks0, st), is_shortvalue(st[r1 -- fs ']), ∀ st, r1, fs, r, val, str. is_shortvalue(st[r1 -- fs ']) ∧ fits(r, sks0, st) → (st[r1 -- fs ', val][r -- sks0]) = st[r -- sks0] ∨ junkref(str, r, st) ⊦ sks0 = [], (st[r1 -- fs ', val][(st[r1 -- fs ', val][r -- sk]) .refval -- sks0]) = st[r -- (sk ' + sks0)], junkref(str, r, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]