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Proof step 56 from proof fits-put-short (conclusion)

⊦ ¬ junkref(str, r, st) ∧ fits(r, sks, st) ∧ is_shortvalue(st[r1 -- fs ']) → (st[r1 -- fs ', val][r -- sks]) = st[r -- sks]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 55:
is_shortvalue(st[r1 -- fs ']), fits(r, sks, st) ⊦ (st[r1 -- fs ', val][r -- sks]) = st[r -- sks], junkref(str, r, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]