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Proof step 23 from proof fits-subset (previous step)

r -- sk ∈ st0 ∧ st0 ⊆ st, st0[r -- sk] = refval(r0), st0[r -- _type] .type = mkclasstype(class), r ∈ st0, sk ∈ instfields(class), fits(r0, sks0, st), st0 ⊆ st, is_obj(str, r, st0), r -- _type ∈ st0, ∀ st0, st, r, str. st0 ⊆ st ∧ fits(r, sks0, st) → junkref(str, r, st0) ∨ fits(r, sks0, st0) ⊦ r = jvmref, junkref(str, r, st0), is_referencevalue(st0[r -- sk]) ∧ fits(st0[r -- sk] .refval, sks0, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 22:
st0[r -- _type] .type = mkclasstype(class), st0[r -- sk] = refval(r0), r -- _type ∈ st0, is_obj(str, r, st0), st0 ⊆ st, fits(r0, sks0, st), sk ∈ instfields(class), r ∈ st0, r -- sk ∈ st0, ∀ st0, st, r, str. st0 ⊆ st ∧ fits(r, sks0, st) → junkref(str, r, st0) ∨ fits(r, sks0, st0) ⊦ r = jvmref, junkref(str, r, st0), fits(r0, sks0, st0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ refval(r) .refval = r], [CSIMPSEQ : ⊦ is_referencevalue(refval(r))])]]