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Proof step 40 from proof fits-subset (previous step)

r -- i ' ∈ st0 ∧ st0 ⊆ st, st0[r -- i '] = refval(r0), r -- _length ∈ st0, r -- _type ∈ st0, is_array(str, r, st0), st0 ⊆ st, fits(r0, sks0, st), is_arraytype(st0[r -- _type] .type), i < st0[r -- _length] .intval, r ∈ st0, 0 ≤ i, 0 < st0[r -- _length] .intval, ∀ st0, st, r, str. st0 ⊆ st ∧ fits(r, sks0, st) → junkref(str, r, st0) ∨ fits(r, sks0, st0) ⊦ r = jvmref, junkref(str, r, st0), is_referencevalue(st0[r -- i ']) ∧ fits(st0[r -- i '] .refval, sks0, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 39:
st0[r -- i '] = refval(r0), 0 < st0[r -- _length] .intval, 0 ≤ i, r ∈ st0, i < st0[r -- _length] .intval, is_arraytype(st0[r -- _type] .type), fits(r0, sks0, st), st0 ⊆ st, is_array(str, r, st0), r -- _type ∈ st0, r -- _length ∈ st0, r -- i ' ∈ st0, ∀ st0, st, r, str. st0 ⊆ st ∧ fits(r, sks0, st) → junkref(str, r, st0) ∨ fits(r, sks0, st0) ⊦ r = jvmref, junkref(str, r, st0), fits(r0, sks0, st0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ refval(r) .refval = r], [CSIMPSEQ : ⊦ is_referencevalue(refval(r))])]]