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Proof step 52 from proof fits-subset (previous step)

st[r -- sk] = refval(r0), st0 ⊆ st, fits(r0, sks0, st), is_classtype(st[r -- _type] .type) → sk ∈ instfields(st[r -- _type] .type .class), is_arraytype(st[r -- _type] .type) → is_indexkey(sk) ∧ 0 ≤ sk .index ∧ sk .index < st[r -- _length] .intval, ∀ st0, st, r, str. st0 ⊆ st ∧ fits(r, sks0, st) → junkref(str, r, st0) ∨ fits(r, sks0, st0) ⊦ r = jvmref, junkref(str, r, st0), r ≠ jvmref ∧ is_referencevalue(st0[r -- sk]) ∧ (is_classtype(st0[r -- _type] .type) → sk ∈ instfields(st0[r -- _type] .type .class)) ∧ (is_arraytype(st0[r -- _type] .type) → is_indexkey(sk) ∧ 0 ≤ sk .index ∧ sk .index < st0[r -- _length] .intval) ∧ fits(st0[r -- sk] .refval, sks0, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 51:
st[r -- sk] = refval(r0), st0 ⊆ st, fits(r0, sks0, st), is_classtype(st[r -- _type] .type) → sk ∈ instfields(st[r -- _type] .type .class), is_arraytype(st[r -- _type] .type) → is_indexkey(sk) ∧ 0 ≤ sk .index ∧ sk .index < st[r -- _length] .intval, ∀ st0, st, r, str. st0 ⊆ st ∧ fits(r, sks0, st) → junkref(str, r, st0) ∨ fits(r, sks0, st0) ⊦ r = jvmref, junkref(str, r, st0), is_referencevalue(st0[r -- sk]) ∧ (is_classtype(st0[r -- _type] .type) → sk ∈ instfields(st0[r -- _type] .type .class)) ∧ (is_arraytype(st0[r -- _type] .type) → ¬ is_fskey(sk) ∧ ¬ sk .index < 0 ∧ ¬ st0[r -- _length] .intval ≤ sk .index) ∧ fits(st0[r -- sk] .refval, sks0, st0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ i < j ↔ j ≤ i], [CSIMPSEQ : ⊦ ¬ i ≤ j ↔ j < i], [CSIMPSEQ : ⊦ ¬ is_indexkey(sk) ↔ is_fskey(sk)])]]