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Proof step 56 from proof fits-subset (previous step)

st0 ⊆ st, r ≠ jvmref ∧ is_referencevalue(st[r -- sk]) ∧ (is_classtype(st[r -- _type] .type) → sk ∈ instfields(st[r -- _type] .type .class)) ∧ (is_arraytype(st[r -- _type] .type) → is_indexkey(sk) ∧ 0 ≤ sk .index ∧ sk .index < st[r -- _length] .intval) ∧ fits(st[r -- sk] .refval, sks0, st), ∀ st0, st, r, str. st0 ⊆ st ∧ fits(r, sks0, st) → junkref(str, r, st0) ∨ fits(r, sks0, st0) ⊦ junkref(str, r, st0), fits(r, sk ' + sks0, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 55:
fits(st[r -- sk] .refval, sks0, st), is_referencevalue(st[r -- sk]), st0 ⊆ st, ∀ st0, st, r, str. st0 ⊆ st ∧ fits(r, sks0, st) → junkref(str, r, st0) ∨ fits(r, sks0, st0), is_arraytype(st[r -- _type] .type) → is_indexkey(sk) ∧ 0 ≤ sk .index ∧ sk .index < st[r -- _length] .intval, is_classtype(st[r -- _type] .type) → sk ∈ instfields(st[r -- _type] .type .class) ⊦ r = jvmref, fits(r, sk ' + sks0, st0), junkref(str, r, st0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]