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Proof step 58 from proof fits-subset (previous step)

∀ st0, st, r, str. st0 ⊆ st ∧ fits(r, sks0, st) → junkref(str, r, st0) ∨ fits(r, sks0, st0), st0 ⊆ st, fits(r, sk + sks0, st) ⊦ junkref(str, r, st0), fits(r, sk + sks0, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 57:
st0 ⊆ st, fits(r, sk ' + sks0, st), ∀ st0, st, r, str. st0 ⊆ st ∧ fits(r, sks0, st) → junkref(str, r, st0) ∨ fits(r, sks0, st0) ⊦ junkref(str, r, st0), fits(r, sk ' + sks0, st0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ sk + sks = sk ' + sks])]]