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Proof step 60 from proof fits-subset (conclusion)

⊦ ¬ junkref(str, r, st0) ∧ fits(r, sks, st) ∧ st0 ⊆ st → fits(r, sks, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]