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Proof step 58 from proof fits-superset (conclusion)
⊦ ¬ junkref(str, r, st) ∧ fits(r, sks, st) ∧ st ⊆ st0 → fits(r, sks, st0)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 57
:
st ⊆ st0, fits(r, sks, st) ⊦ junkref(str, r, st), fits(r, sks, st0)
Rule argument
[emptyarg]
Additional information
[[CONCRETESIMPRULES : ()]]