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Proof step 107 from proof hasSharing-addobj-same (previous step)

fis .keys = instfields(class), dups(fis .vals .nonnullrefs), newref(r, st), validfieldinits(str, fis, st) ⊦ r = jvmref, hasSharing(r, addobj(r, class, fis, st)), junkref(str, r, addobj(r, class, fis, st))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 93:
⊦ hasSharing(r, st) ↔ (∃ sks1, sks2. fits(r, sks1, st) ∧ fits(r, sks2, st) ∧ sks1 ≠ sks2 ∧ st[r -- sks1] .refval ≠ jvmref ∧ st[r -- sks1] = st[r -- sks2])
Proof step 106:
fis .keys = instfields(class), dups(fis .vals .nonnullrefs), newref(r, st), validfieldinits(str, fis, st) ⊦ r = jvmref, ∃ sks1, sks2. fits(r, sks1, addobj(r, class, fis, st)) ∧ fits(r, sks2, addobj(r, class, fis, st)) ∧ sks1 ≠ sks2 ∧ (addobj(r, class, fis, st)[r -- sks1]) .refval ≠ jvmref ∧ (addobj(r, class, fis, st)[r -- sks1]) = (addobj(r, class, fis, st)[r -- sks2]), junkref(str, r, addobj(r, class, fis, st))

Rule argument

[x0lemmaarg: spec-name: instance-name: lemma-name: hasSharing-def-better antecedent: succedent: hasSharing(r, st) ↔ (∃ sks1, sks2. fits(r, sks1, st) ∧ fits(r, sks2, st) ∧ sks1 ≠ sks2 ∧ st[r -- sks1] .refval ≠ jvmref ∧ st[r -- sks1] = st[r -- sks2]) substlist: [st, r] → [addobj(r, class, fis, st), r] add preconditions?: F is rewrite lemma?: T current spec?: T rotate lemma?: F replace all?: T paths: ((1, 0, 1)) dummy: () ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (addobj(r, class, fis, st), r)]]