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Proof step 162 from proof hasSharing-addobj-same (previous step)

¬ dups(fis .keys), st[r0 -- sks0] = refval(r1), fis .keys = instfields(class), st[r0 -- sks] = refval(r1), r0 ≠ jvmref ∧ (∃ sk. fis[sk] = refval(r0) ∧ sk ∈ fis), fits(r0, sks, st), fits(r0, sks0, st), newref(r, st), validfieldinits(str, fis, st) ⊦ sks0 = sks, sks0 = [], sks = [], r1 = jvmref, r = jvmref, dups(fis .vals .nonnullrefs), ∃ sks1, sks2. fits(r, sks1, addobj(r, class, fis, st)) ∧ fits(r, sks2, addobj(r, class, fis, st)) ∧ sks1 ≠ sks2 ∧ (addobj(r, class, fis, st)[r -- sks1]) .refval ≠ jvmref ∧ (addobj(r, class, fis, st)[r -- sks1]) = (addobj(r, class, fis, st)[r -- sks2]), junkref(str, r, addobj(r, class, fis, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 161:
fis[sk] = refval(r0), st[r0 -- sks] = refval(r1), fis .keys = instfields(class), st[r0 -- sks0] = refval(r1), validfieldinits(str, fis, st), newref(r, st), fits(r0, sks0, st), fits(r0, sks, st), sk ∈ fis ⊦ r0 = jvmref, r = jvmref, r1 = jvmref, sks = [], sks0 = [], sks0 = sks, junkref(str, r, addobj(r, class, fis, st)), dups(fis .vals .nonnullrefs), ∃ sks1, sks2. fits(r, sks1, addobj(r, class, fis, st)) ∧ fits(r, sks2, addobj(r, class, fis, st)) ∧ sks1 ≠ sks2 ∧ (addobj(r, class, fis, st)[r -- sks1]) .refval ≠ jvmref ∧ (addobj(r, class, fis, st)[r -- sks1]) = (addobj(r, class, fis, st)[r -- sks2])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : addfuns, , instfields-nodups, ⊦ ¬ dups(instfields(class))])]]