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Proof step 188 from proof hasSharing-addobj-same (previous step)

sks ≠ [], fis[sk] = refval(r0), st[r0 -- sks] = refval(r2), st[r3 -- sks0] = refval(r2), fis[sk0] = refval(r3), sk0 ∈ fis .keys, sk ∈ fis .keys, sk0 ∈ fis, sk ∈ fis, fits(r3, sks0, st), fits(r0, sks, st), newref(r, st), validfieldinits(str, fis, st) ⊦ r0 = jvmref, r = jvmref, r2 = jvmref, r3 = r0, r3 = jvmref, sk = sk0, hasSharing(fis .vals .nonnullrefs, st), dups(fis .vals .nonnullrefs), junkref(str, r, addobj(r, class, fis, st)), junkref(str, r0, st), junkref(str, r3, st), is_referencevalue(addobj(r, class, fis, st)[(addobj(r, class, fis, st)[r -- sk]) .refval -- sks])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 187:
fis[sk0] = refval(r3), st[r3 -- sks0] = refval(r2), st[r0 -- sks] = refval(r2), fis[sk] = refval(r0), validfieldinits(str, fis, st), newref(r, st), fits(r0, sks, st), fits(r3, sks0, st), sk ∈ fis, sk0 ∈ fis, sk ∈ fis .keys, sk0 ∈ fis .keys ⊦ sks = [], sk = sk0, r3 = jvmref, r3 = r0, r2 = jvmref, r = jvmref, r0 = jvmref, junkref(str, r3, st), junkref(str, r0, st), junkref(str, r, addobj(r, class, fis, st)), dups(fis .vals .nonnullrefs), hasSharing(fis .vals .nonnullrefs, st), is_referencevalue(addobj(r, class, fis, st)[r0 -- sks])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : javavalue, , sel-09, ⊦ refval(r) .refval = r], [CSIMPNAMEDSEQ : addfuns, , add-in-09, ⊦ sk ∈ fis → (addobj(r, class, fis, st) [r -- sk ] ) = fis[sk]])]]