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Proof step 204 from proof hasSharing-addobj-same (previous step)

fis[sk] = refval(r0), st[r0 -- sks] = refval(r2), st[r3 -- sks0] = refval(r2), fis[sk0] = refval(r3), sk0 ∈ fis .keys, sk ∈ fis .keys, sk0 ∈ fis, sk ∈ fis, fits(r3, sks0, st), fits(r0, sks, st), newref(r, st), validfieldinits(str, fis, st) ⊦ r0 = jvmref, r = jvmref, r2 = jvmref, r3 = r0, r3 = jvmref, sk = sk0, hasSharing(fis .vals .nonnullrefs, st), dups(fis .vals .nonnullrefs), junkref(str, r, addobj(r, class, fis, st)), junkref(str, r0, st), junkref(str, r3, st), (addobj(r, class, fis, st)[r -- (sk ' + sks)]) .refval ≠ jvmref ∧ (addobj(r, class, fis, st)[r -- (sk ' + sks)]) = (addobj(r, class, fis, st)[r -- (sk0 ' + sks0)])

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

[x0lemmaarg: spec-name: storefuns instance-name: lemma-name: lookup-rec-refval antecedent: succedent: is_referencevalue(st[r -- sks]) ∧ sks ≠ [] → st[r -- sks] = st[st[r -- sks .first] .refval -- sks .rest] substlist: [sks, r, st] → [sk ' + sks, r, addobj(r, class, fis, st)] add preconditions?: F is rewrite lemma?: T current spec?: F rotate lemma?: F replace all?: T paths: ((1, 0, 11, 1, 0, 1, 0, 1, 0)) dummy: () ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (sk ' + sks, r, addobj(r, class, fis, st))]]