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Proof step 218 from proof hasSharing-addobj-same (previous step)

refval(r1) = refval(r3) ∧ is_referencevalue(refval(r1)), fis[sk0] = refval(r1), fis .keys = instfields(class), st[r1 -- sks0] = refval(r2), st[r0 -- sks] = refval(r2), fis[sk] = refval(r0), validfieldinits(str, fis, st), newref(r, st), fits(r0, sks, st), fits(r1, sks0, st), sk ∈ fis, sk0 ∈ fis ⊦ sk = sk0, r1 = jvmref, r1 = r0, r2 = jvmref, r = jvmref, r0 = jvmref, junkref(str, r, addobj(r, class, fis, st)), dups(fis .vals .nonnullrefs), hasSharing(fis .vals .nonnullrefs, st), sk ∈ instfields(class) ∧ fits(r0, sks, addobj(r, class, fis, st)) ∧ fits(r3, sks0, addobj(r, class, fis, st)) ∧ sk0 ∈ instfields(class) ∧ (addobj(r, class, fis, st)[r -- (sk ' + sks)]) .refval ≠ jvmref ∧ (addobj(r, class, fis, st)[r -- (sk ' + sks)]) = (addobj(r, class, fis, st)[r -- (sk0 ' + sks0)])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 217:
fis[sk] = refval(r0), st[r0 -- sks] = refval(r2), st[r3 -- sks0] = refval(r2), fis .keys = instfields(class), fis[sk0] = refval(r3), sk0 ∈ fis, sk ∈ fis, fits(r3, sks0, st), fits(r0, sks, st), newref(r, st), validfieldinits(str, fis, st) ⊦ r0 = jvmref, r = jvmref, r2 = jvmref, r3 = r0, r3 = jvmref, sk = sk0, hasSharing(fis .vals .nonnullrefs, st), dups(fis .vals .nonnullrefs), junkref(str, r, addobj(r, class, fis, st)), sk ∈ instfields(class) ∧ fits(r0, sks, addobj(r, class, fis, st)) ∧ fits(r3, sks0, addobj(r, class, fis, st)) ∧ sk0 ∈ instfields(class) ∧ (addobj(r, class, fis, st)[r -- (sk ' + sks)]) .refval ≠ jvmref ∧ (addobj(r, class, fis, st)[r -- (sk ' + sks)]) = (addobj(r, class, fis, st)[r -- (sk0 ' + sks0)])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : javavalue, , test-19, ⊦ is_referencevalue(refval(r))], [CSIMPNAMEDSEQ : javavalue, , inj-03, ⊦ refval(r) = refval(r0) ↔ r = r0])]]