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Proof step 231 from proof hasSharing-addobj-same (previous step)

fis .keys = instfields(class), st[r1 -- sks0] = refval(r2), st[r0 -- sks] = refval(r2), validfieldinits(str, fis, st), newref(r, st), validreflist(str, mkjavavalues(fis .vals .nonnullrefs), mkclasstype(`java.lang.Object' .class), st), fits(r0, sks, st), fits(r1, sks0, st), r0 ∈ fis .vals .nonnullrefs, r1 ∈ fis .vals .nonnullrefs ⊦ r1 = r0, r2 = jvmref, r = jvmref, junkref(str, r, addobj(r, class, fis, st)), ∃ sks1, sks2. fits(r, sks1, addobj(r, class, fis, st)) ∧ fits(r, sks2, addobj(r, class, fis, st)) ∧ sks1 ≠ sks2 ∧ (addobj(r, class, fis, st)[r -- sks1]) .refval ≠ jvmref ∧ (addobj(r, class, fis, st)[r -- sks1]) = (addobj(r, class, fis, st)[r -- sks2]), dups(fis .vals .nonnullrefs), hasSharing(fis .vals .nonnullrefs, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 230:
fis .keys = instfields(class), st[r1 -- sks0] = refval(r2), st[r0 -- sks] = refval(r2), validfieldinits(str, fis, st), newref(r, st), fits(r0, sks, st), fits(r1, sks0, st), r0 ∈ fis .vals .nonnullrefs, r1 ∈ fis .vals .nonnullrefs ⊦ r1 = r0, r2 = jvmref, r = jvmref, junkref(str, r, addobj(r, class, fis, st)), dups(fis .vals .nonnullrefs), hasSharing(fis .vals .nonnullrefs, st), ∃ sks1, sks2. fits(r, sks1, addobj(r, class, fis, st)) ∧ fits(r, sks2, addobj(r, class, fis, st)) ∧ sks1 ≠ sks2 ∧ (addobj(r, class, fis, st)[r -- sks1]) .refval ≠ jvmref ∧ (addobj(r, class, fis, st)[r -- sks1]) = (addobj(r, class, fis, st)[r -- sks2])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : junkrefs, , validfieldinits-validreflist, ⊦ validfieldinits (str, fis, st) → validreflist (str, mkjavavalues (fis .vals .nonnullrefs), mkclasstype (`java.lang.Object' .class), st)])]]