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Proof step 39 from proof hasSharing-addobj-same (
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⊦ fis[sk] = refval(r) ∧ fis[sk0] = refval(r) ∧ sk ≠ sk0 ∧ sk ∈ fis ∧ sk0 ∈ fis ∧ r ≠ jvmref → dups(fis .vals .nonnullrefs)
A spec-lemma