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Proof step 54 from proof hasSharing-addobj-same (previous step)

st[r2 -- sks] = refval(r0), fis .keys = instfields(class), st[r1 -- sks1] = refval(r0), fis[sk] = refval(r1), fis[sk0] = refval(r2), validreflist(str, mkjavavalues(fis .vals .nonnullrefs), mkclasstype(`java.lang.Object' .class), st), r2 -- sks ∈ st, r1 -- sks1 ∈ st, sk0 ∈ fis, sk0 ∈ instfields(class), fits(r2, sks, st), newref(r, st), validfieldinits(str, fis, st), sk ∈ fis, is_referencevalue(addobj(r, class, fis, st)[r -- (sk0 ' + sks)]), is_referencevalue(addobj(r, class, fis, st)[r -- (sk ' + sks1)]), sk ∈ instfields(class), fits(r1, sks1, st), ¬ r1 ∈ fis .vals .nonnullrefs ∨ ¬ r2 ∈ fis .vals .nonnullrefs ∨ r1 = r2 ∨ ¬ fits(r1, sks1, st) ∨ ¬ fits(r2, sks, st) ∨ st[r1 -- sks1] ≠ st[r2 -- sks] ∨ st[r1 -- sks1] .refval = jvmref ⊦ r1 = r2, sk = sk0, r = jvmref, sk0 ' + sks = sk ' + sks1, r0 = jvmref, dups(fis .vals .nonnullrefs), hasSharing(fis .vals .nonnullrefs, st), junkref(str, r, addobj(r, class, fis, st)), junkref(str, r1, st), junkref(str, r2, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : javavalue, , sel-09, ⊦ refval(r) .refval = r])]]