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Proof step 75 from proof hasSharing-addobj-same (previous step)

is_referencevalue(addobj(r, class, fis, st)[r -- sks0]) ∧ sks0 ≠ [], (addobj(r, class, fis, st)[(addobj(r, class, fis, st)[r -- sks0 .first]) .refval -- sks0 .rest]) = refval(r0), fis .keys = instfields(class), (addobj(r, class, fis, st)[r1 -- sks1]) = refval(r0), fis[sk] = refval(r1), disjoint(str, fis .vals .nonnullrefs, st), is_referencevalue(addobj(r, class, fis, st)[r -- (sk ' + sks1)]), sk ∈ instfields(class), fits(r1, sks1, addobj(r, class, fis, st)), fits(r, sks0, addobj(r, class, fis, st)), newref(r, st), validfieldinits(str, fis, st), sk ∈ fis ⊦ r = jvmref, sks0 = sk ' + sks1, sks0 = [], r0 = jvmref, dups(fis .vals .nonnullrefs), hasSharing(fis .vals .nonnullrefs, st), junkref(str, r, addobj(r, class, fis, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 74:
fis[sk] = refval(r1), (addobj(r, class, fis, st)[r1 -- sks1]) = refval(r0), fis .keys = instfields(class), (addobj(r, class, fis, st)[(addobj(r, class, fis, st)[r -- sks0 .first]) .refval -- sks0 .rest]) = refval(r0), sk ∈ fis, validfieldinits(str, fis, st), newref(r, st), fits(r, sks0, addobj(r, class, fis, st)), fits(r1, sks1, addobj(r, class, fis, st)), sk ∈ instfields(class), is_referencevalue(addobj(r, class, fis, st)[r -- (sk ' + sks1)]), disjoint(str, fis .vals .nonnullrefs, st), is_referencevalue(addobj(r, class, fis, st)[r -- sks0]) ⊦ sks0 = [], r0 = jvmref, sks0 = sk ' + sks1, r = jvmref, junkref(str, r, addobj(r, class, fis, st)), hasSharing(fis .vals .nonnullrefs, st), dups(fis .vals .nonnullrefs)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]