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Proof step 85 from proof hasSharing-addobj-same (previous step)

(addobj(r, class, fis, st)[(addobj(r, class, fis, st)[r -- sks .first]) .refval -- sks .rest]) = refval(r0), fis .keys = instfields(class), (addobj(r, class, fis, st)[r -- sks0]) = refval(r0), validfieldinits(str, fis, st), newref(r, st), fits(r, sks0, addobj(r, class, fis, st)), fits(r, sks, addobj(r, class, fis, st)), disjoint(str, fis .vals .nonnullrefs, st), is_referencevalue(addobj(r, class, fis, st)[r -- sks]) ⊦ sks = [], r = jvmref, r0 = jvmref, sks0 = [], sks0 = sks, junkref(str, r, addobj(r, class, fis, st)), hasSharing(fis .vals .nonnullrefs, st), dups(fis .vals .nonnullrefs)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

[x0lemmaarg: spec-name: list-data instance-name: storekeys lemma-name: elim-list-c antecedent: sks ≠ [] succedent: sk = sks .first ∧ sks0 = sks .rest ↔ sks = sk + sks0 substlist: [sks, sk, sks0] → [sks, sk, sks1] add preconditions?: F is rewrite lemma?: F current spec?: F rotate lemma?: T replace all?: T paths: () dummy: () ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : sks ≠ [] ⊦ sk = sks .first ∧ sks0 = sks .rest ↔ sks = sk + sks0])], [EXTRATERMS : (sks, sk, sks1)]]