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Proof step 90 from proof hasSharing-addobj-same (previous step)

fis .keys = instfields(class), validfieldinits(str, fis, st), newref(r, st), ∃ sks1, sks2. fits(r, sks1, addobj(r, class, fis, st)) ∧ fits(r, sks2, addobj(r, class, fis, st)) ∧ sks1 ≠ sks2 ∧ sks1 ≠ [] ∧ sks2 ≠ [] ∧ (addobj(r, class, fis, st)[r -- sks1]) .refval ≠ jvmref ∧ (addobj(r, class, fis, st)[r -- sks1]) = (addobj(r, class, fis, st)[r -- sks2]), disjoint(str, fis .vals .nonnullrefs, st) ⊦ r = jvmref, junkref(str, r, addobj(r, class, fis, st)), hasSharing(fis .vals .nonnullrefs, st), dups(fis .vals .nonnullrefs)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 89:
fis .keys = instfields(class), (addobj(r, class, fis, st)[r -- sks0]) = (addobj(r, class, fis, st)[r -- sks]), validfieldinits(str, fis, st), newref(r, st), fits(r, sks0, addobj(r, class, fis, st)), fits(r, sks, addobj(r, class, fis, st)), disjoint(str, fis .vals .nonnullrefs, st) ⊦ r = jvmref, (addobj(r, class, fis, st)[r -- sks]) .refval = jvmref, sks = [], sks0 = [], sks0 = sks, junkref(str, r, addobj(r, class, fis, st)), hasSharing(fis .vals .nonnullrefs, st), dups(fis .vals .nonnullrefs)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]