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Proof step 10 from proof hasSharing-array-forward (previous step)

sks0 ≠ [], st[r0 -- sks] = refval(r1), st[r -- i '] = refval(r0), st[r0 -- sks0] = refval(r1), fits(r0, sks0, st), fits(r0, sks, st), i < st[r -- _length] .intval, is_arraytype(st[r -- _type] .type), 0 ≤ i, 0 < st[r -- _length] .intval ⊦ sks = [], r = jvmref, r1 = jvmref, sks0 = [], sks0 = sks, fits(r, i ' ' + sks0, st) ∧ fits(r, i ' ' + sks, st) ∧ st[st[r -- i '] .refval -- sks0] .refval ≠ jvmref ∧ st[st[r -- i '] .refval -- sks0] = refval(r1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
st[r0 -- sks] = refval(r1), st[r -- i '] = refval(r0), st[r0 -- sks0] = refval(r1), fits(r0, sks0, st), fits(r0, sks, st), i < st[r -- _length] .intval, is_arraytype(st[r -- _type] .type), 0 ≤ i, 0 < st[r -- _length] .intval ⊦ sks = [], r = jvmref, r1 = jvmref, sks0 = sks, sks0 = [], fits(r, i ' ' + sks0, st) ∧ fits(r, i ' ' + sks, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ refval(r) .refval = r])]]