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Proof step 12 from proof hasSharing-array-forward (previous step)

sks ≠ [], st[r0 -- sks0] = refval(r1), st[r -- i '] = refval(r0), st[r0 -- sks] = refval(r1), 0 < st[r -- _length] .intval, 0 ≤ i, is_arraytype(st[r -- _type] .type), i < st[r -- _length] .intval, fits(r0, sks, st), fits(r0, sks0, st) ⊦ sks0 = sks, sks0 = [], sks = [], r1 = jvmref, r = jvmref, fits(r, i ' ' + sks0, st) ∧ fits(r, i ' ' + sks, st) ∧ st[r -- (i ' ' + sks0)] .refval ≠ jvmref ∧ st[r -- (i ' ' + sks0)] = st[st[r -- i '] .refval -- sks]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
st[r0 -- sks] = refval(r1), st[r -- i '] = refval(r0), st[r0 -- sks0] = refval(r1), fits(r0, sks0, st), fits(r0, sks, st), i < st[r -- _length] .intval, is_arraytype(st[r -- _type] .type), 0 ≤ i, 0 < st[r -- _length] .intval ⊦ sks = [], r = jvmref, r1 = jvmref, sks0 = [], sks0 = sks, fits(r, i ' ' + sks0, st) ∧ fits(r, i ' ' + sks, st) ∧ st[r -- (i ' ' + sks0)] .refval ≠ jvmref ∧ st[r -- (i ' ' + sks0)] = refval(r1)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ refval(r) .refval = r])]]