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Proof step 141 from proof hasSharing-dd-help (previous step)

refs0 = refs1 + r0 ', r1 ' + refs0 = refs + r0 ', r1 ∈ refs, path∃(str, r, r2, st), path∃(str, r, r1, st), validrefs(str, r2 ' + refs2 + r0 ', st[r2 -- _type] .type, st), validrefs(str, r1 ' + refs0, st[r1 -- _type] .type, st) ⊦ refs0 = [], r2 = r1, r0 = jvmref, r1 = r0, hasSharing(r, st), path∃(str, r1, r2, st), path∃(str, r2, r1, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 140:
validrefs(str, r1 ' + refs1 + r0 ', st[r1 -- _type] .type, st), validrefs(str, r2 ' + refs2 + r0 ', st[r2 -- _type] .type, st), path∃(str, r, r1, st), path∃(str, r, r2, st) ⊦ r1 = r0, r0 = jvmref, r2 = r1, path∃(str, r2, r1, st), path∃(str, r1, r2, st), hasSharing(r, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r ∈ r0 ' ↔ r = r0], [CSIMPSEQ : ⊦ r ∈ refs + refs0 ↔ ¬ ¬ (r ∈ refs ∨ r ∈ refs0)], [CSIMPFORWARD : ⊦ r ' + refs = refs0 → r ∈ refs0], [CSIMPSEQ : ⊦ refs + r ' ≠ []], [CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ refs + refs0 = refs1 + refs0 ↔ refs = refs1])]]