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Proof step 145 from proof hasSharing-dd-help (previous step)

r1 ' + refs0 = refs + r0 ' ∧ r1 ' + refs0 ≠ [], refs1 .last = r0, validrefs(str, r1 ' + refs0, st[r1 -- _type] .type, st), validrefs(str, r2 ' + refs1, st[r2 -- _type] .type, st), path∃(str, r, r1, st), path∃(str, r, r2, st) ⊦ refs1 .last = jvmref, r2 = r1, refs1 = [], path∃(str, r2, r1, st), path∃(str, r1, r2, st), hasSharing(r, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 144:
r1 ' + refs0 = refs + refs1 .last ', path∃(str, r, r2, st), path∃(str, r, r1, st), validrefs(str, r2 ' + refs1, st[r2 -- _type] .type, st), validrefs(str, r1 ' + refs0, st[r1 -- _type] .type, st) ⊦ refs1 = [], r2 = r1, refs1 .last = jvmref, hasSharing(r, st), path∃(str, r1, r2, st), path∃(str, r2, r1, st), ¬ r1 ∈ refs ∧ r1 ≠ refs1 .last, refs1 .last ≠ r1 ∧ ¬ refs1 .last ∈ refs0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r ∈ r0 ' ↔ r = r0], [CSIMPSEQ : ⊦ r ∈ refs + refs0 ↔ ¬ ¬ (r ∈ refs ∨ r ∈ refs0)], [CSIMPFORWARD : ⊦ refs + r ' = refs0 → r ∈ refs0], [CSIMPFORWARD : ⊦ r ' + refs = refs0 → r ∈ refs0], [CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ r ' + refs ≠ []])]]