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Proof step 148 from proof hasSharing-dd-help (conclusion)

(r2 ' + refs1) .last = (r1 ' + refs0) .last, validrefs(str, r1 ' + refs0, st[r1 -- _type] .type, st), validrefs(str, r2 ' + refs1, st[r2 -- _type] .type, st), path∃(str, r, r1, st), path∃(str, r, r2, st) ⊦ (r1 ' + refs0) .last = jvmref, r2 = r1, path∃(str, r2, r1, st), path∃(str, r1, r2, st), hasSharing(r, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ refs ≠ [] → (r ' + refs) .last = refs .last
Proof step 6:
¬ refs1 ≠ [], (r2 ' + refs1) .last = (r1 ' + refs0) .last, validrefs(str, r1 ' + refs0, st[r1 -- _type] .type, st), validrefs(str, r2 ' + refs1, st[r2 -- _type] .type, st), path∃(str, r, r1, st), path∃(str, r, r2, st) ⊦ (r1 ' + refs0) .last = jvmref, r2 = r1, path∃(str, r2, r1, st), path∃(str, r1, r2, st), hasSharing(r, st)
Proof step 147:
refs1 ≠ [], refs1 .last = (r1 ' + refs0) .last, validrefs(str, r1 ' + refs0, st[r1 -- _type] .type, st), validrefs(str, r2 ' + refs1, st[r2 -- _type] .type, st), path∃(str, r, r1, st), path∃(str, r, r2, st) ⊦ (r1 ' + refs0) .last = jvmref, r2 = r1, path∃(str, r2, r1, st), path∃(str, r1, r2, st), hasSharing(r, st)

Rule argument

[speclemmaarg: ,refs ≠ [] → (r ' + refs) .last = refs .last ,[refs, r] → [refs1, r2] ,F ,list-last ,references ,l-02 ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (refs1, r2)]]