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Proof step 18 from proof hasSharing-dd-help (previous step)

# refs1 = # refs2, # refs = # refs0, # sks0 = 2 + # refs2 + # refs0, validrefs(str, (r ' + refs) + r1 ' + refs1 + r0 ', st[r -- _type] .type, st), validrefs(str, (r ' + refs0) + st[r -- firstn(1 + # refs0, sks0)] .refval ' + refs2 + r0 ', st[r -- _type] .type, st), fits(r, sks0, st) ⊦ ¬ # sks0 ≤ # refs0, st[r -- firstn(1 + # refs0, sks0)] .refval = r1, r1 = r0, r0 = jvmref, path∃(str, st[r -- firstn(1 + # refs0, sks0)] .refval, r1, st), path∃(str, r1, st[r -- firstn(1 + # refs0, sks0)] .refval, st), hasSharing(r, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
# sks0 = 2 + # refs2 + # refs0, # refs = # refs0, # refs1 = # refs2, fits(r, sks0, st), validrefs(str, (r ' + refs0) + st[r -- firstn(1 + # refs0, sks0)] .refval ' + refs2 + r0 ', st[r -- _type] .type, st), validrefs(str, (r ' + refs) + r1 ' + refs1 + r0 ', st[r -- _type] .type, st), # sks0 ≤ # refs0 ⊦ r0 = jvmref, r1 = r0, st[r -- firstn(1 + # refs0, sks0)] .refval = r1, hasSharing(r, st), path∃(str, r1, st[r -- firstn(1 + # refs0, sks0)] .refval, st), path∃(str, st[r -- firstn(1 + # refs0, sks0)] .refval, r1, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]