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Proof step 50 from proof hasSharing-dd-help (previous step)

st[r -- firstn(1 + # refs, sks0)] .refval = refs0[# refs], # refs + # refs1 = # refs2 + # refs0, # sks0 = 2 + # refs2 + # refs0, fits(r, sks0, st), validrefs(str, (r ' + refs0) + r2 ' + refs2 + r0 ', st[r -- _type] .type, st), validrefs(str, (r ' + refs) + st[r -- firstn(1 + # refs, sks0)] .refval ' + refs1 + r0 ', st[r -- _type] .type, st), # refs < # refs0 ⊦ r0 = jvmref, st[r -- firstn(1 + # refs, sks0)] .refval = r0, r2 = st[r -- firstn(1 + # refs, sks0)] .refval, # refs = # refs0, refs0 = [], hasSharing(r, st), path∃(str, st[r -- firstn(1 + # refs, sks0)] .refval, r2, st), path∃(str, r2, st[r -- firstn(1 + # refs, sks0)] .refval, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 49:
st[r -- firstn(1 + # refs, sks0)] .refval = refs0[# refs], # refs + # refs1 = # refs2 + # refs0, # sks0 = 2 + # refs2 + # refs0, fits(r, sks0, st), validrefs(str, (r ' + refs0) + r2 ' + refs2 + r0 ', st[r -- _type] .type, st), validrefs(str, (r ' + refs) + refs0[# refs] ' + refs1 + r0 ', st[r -- _type] .type, st), # refs < # refs0 ⊦ r0 = jvmref, refs0[# refs] = r0, r2 = refs0[# refs], # refs = # refs0, refs0 = [], hasSharing(r, st), path∃(str, refs0[# refs], r2, st), path∃(str, r2, refs0[# refs], st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]