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Proof step 9 from proof hasSharing-dups-array (previous step)

st[r -- i '] = refval(r0), st[r -- j '] = refval(r0), 0 < st[r -- _length] .intval, 0 ≤ j, 0 ≤ i, is_arraytype(st[r -- _type] .type), j < st[r -- _length] .intval, i < st[r -- _length] .intval ⊦ r = jvmref, i = j, r0 = jvmref, hasSharing(r, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ hasSharing(r, st) ↔ (∃ sks1, sks2. fits(r, sks1, st) ∧ fits(r, sks2, st) ∧ sks1 ≠ sks2 ∧ sks1 ≠ [] ∧ sks2 ≠ [] ∧ st[r -- sks1] .refval ≠ jvmref ∧ st[r -- sks1] = st[r -- sks2])
Proof step 8:
st[r -- i '] = refval(r0), st[r -- j '] = refval(r0), 0 < st[r -- _length] .intval, 0 ≤ j, 0 ≤ i, is_arraytype(st[r -- _type] .type), j < st[r -- _length] .intval, i < st[r -- _length] .intval ⊦ r = jvmref, i = j, r0 = jvmref, ∃ sks1, sks2. fits(r, sks1, st) ∧ fits(r, sks2, st) ∧ sks1 ≠ sks2 ∧ sks1 ≠ [] ∧ sks2 ≠ [] ∧ st[r -- sks1] .refval ≠ jvmref ∧ st[r -- sks1] = st[r -- sks2]

Rule argument

[crewrite-arg: hasSharing-def, F, [st, r] → [st, r]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, r)]]