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Proof step 67 from proof hasSharing-pathex (previous step)

path∃(str, r, r0, st), hasSharing(r0, st) ⊦ hasSharing(r, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ path∃(str, r, r0, st) ↔ (∃ refs. refs ≠ [] ∧ refs .first = r ∧ refs .last = r0 ∧ validrefs(str, refs, st[r -- _type] .type, st))
Proof step 66:
∃ refs. refs ≠ [] ∧ refs .first = r ∧ refs .last = r0 ∧ validrefs(str, refs, st[r -- _type] .type, st), hasSharing(r0, st) ⊦ hasSharing(r, st)

Rule argument

[speclemmaarg: , path∃(str, r, r0, st) ↔ (∃ refs. refs ≠ [] ∧ refs .first = r ∧ refs .last = r0 ∧ validrefs(str, refs, st[r -- _type] .type, st)) ,[st, r0, r, str] → [st, r0, r, str] ,F ,cyclic , ,pathex-def-simple ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, r0, r, str)]]