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Proof step 108 from proof hasSharing-put-index-refval (previous step)

st[r0 -- _type] .type = mkarraytype(ty), (st[r0 -- i ', refval(r1)][r0 -- sks0]) = refval(r1), disjoint(str, r0 ' + r1 ', st), validref(str, r1, ty, st), fits(r0, sks0, st), i < st[r0 -- _length] .intval, 0 ≤ i, 0 < st[r0 -- _length] .intval ⊦ sks0 = i ' ', r0 = jvmref, r0 = r1, r1 = jvmref, sks0 = [], junkref(str, r0, st), hasSharing(r1, st), hasSharing(r0, st), ∃ sks, sks1. sks0 = sks + i ' ' + sks1 ∧ st[r0 -- sks] .refval = r0 ∧ (∀ sks2. sks2 + i ' ' ⊑ sks → st[r0 -- sks2] .refval ≠ r0)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

[x0lemmaarg: spec-name: storefuns instance-name: lemma-name: lookup-put-other antecedent: succedent: ¬ (∃ sks0, sks1. sks = sks0 + (sk + sks1) ∧ st[r -- sks0] .refval = r0 ∧ (∀ sks2. sks2 + sk ⊑ sks0 → st[r -- sks2] .refval ≠ r0)) → (st[r0 -- sk, val][r -- sks]) = st[r -- sks] substlist: [sks, r, val, sk, r0, st] → [sks0, r0, refval(r1), i ', r0, st] add preconditions?: F is rewrite lemma?: T current spec?: F rotate lemma?: F replace all?: T paths: ((0, 0, 1, 1, 0)) dummy: () ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (sks0, r0, refval(r1), i ', r0, st)]]