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Proof step 142 from proof hasSharing-put-index-refval (previous step)

sks + i ' ' + sks0 ≠ [], (st[r -- i ', refval(r2)][r2 -- sks]) = refval(r0), st[r2 -- sks] = refval(r), (st[r -- i ', refval(r2)][r2 -- (sks + i ' ' + sks0)]) = refval(r1), st[r -- _type] .type = mkarraytype(ty), (st[r -- i ', refval(r2)][r2 -- sks3]) = refval(r1), (st[r -- i ', refval(r2)][r0 -- i ']) = refval(r3), fits(r3, sks0, st[r -- i ', refval(r2)]), fits(r2, sks, st), is_referencevalue(st[r -- i ', refval(r2)][(st[r -- i ', refval(r2)][r -- i ']) .refval -- (sks + i ' ' + sks0)]), 0 < st[r -- _length] .intval, validref(str, r2, ty, st), disjoint(str, r ' + r2 ', st), fits(r2, sks3, st[r -- i ', refval(r2)]), 0 ≤ i, i < st[r -- _length] .intval, is_arraytype(st[r0 -- _type] .type) → i < st[r0 -- _length] .intval ⊦ r0 = jvmref, sks + i ' ' + sks0 = sks3, sks3 = [], r2 = jvmref, r1 = jvmref, r = r2, r = jvmref, is_classtype(st[r0 -- _type] .type), hasSharing(r, st), hasSharing(r2, st), junkref(str, r, st), ∃ sks1, sks4. sks = sks1 + i ' ' + sks4 ∧ st[r2 -- sks1] .refval = r ∧ (∀ sks2. sks2 + i ' ' ⊑ sks1 → st[r2 -- sks2] .refval ≠ st[r2 -- sks1] .refval), ∃ sks2. ¬ (sks2 + i ' ' ⊑ sks → st[r2 -- sks2] .refval ≠ r)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 141:
(st[r -- i ', refval(r2)][r0 -- i ']) = refval(r3), (st[r -- i ', refval(r2)][r2 -- sks3]) = refval(r1), st[r -- _type] .type = mkarraytype(ty), (st[r -- i ', refval(r2)][r2 -- (sks + i ' ' + sks0)]) = refval(r1), st[r2 -- sks] = refval(r), (st[r -- i ', refval(r2)][r2 -- sks]) = refval(r0), fits(r2, sks, st), fits(r3, sks0, st[r -- i ', refval(r2)]), i < st[r -- _length] .intval, 0 ≤ i, fits(r2, sks3, st[r -- i ', refval(r2)]), disjoint(str, r ' + r2 ', st), validref(str, r2, ty, st), 0 < st[r -- _length] .intval, is_arraytype(st[r0 -- _type] .type) → i < st[r0 -- _length] .intval ⊦ r = jvmref, r = r2, r1 = jvmref, r2 = jvmref, sks3 = [], sks + i ' ' + sks0 = sks3, r0 = jvmref, junkref(str, r, st), hasSharing(r2, st), hasSharing(r, st), is_classtype(st[r0 -- _type] .type), ∃ sks2. ¬ (sks2 + i ' ' ⊑ sks → st[r2 -- sks2] .refval ≠ r), ∃ sks1, sks4. sks = sks1 + i ' ' + sks4 ∧ st[r2 -- sks1] .refval = r ∧ (∀ sks2. sks2 + i ' ' ⊑ sks1 → st[r2 -- sks2] .refval ≠ st[r2 -- sks1] .refval)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : javavalue, , test-19, ⊦ is_referencevalue(refval(r))], [CSIMPNAMEDSEQ : javavalue, , sel-09, ⊦ refval(r) .refval = r], [CSIMPNAMEDSEQ : store, javastore, At-same, ⊦ (st[rk, val][rk]) = val], [CSIMPNAMEDSEQ : list, storekeys, a, ⊦ (sks + sks0) + sks1 = sks + sks0 + sks1], [CSIMPNAMEDSEQ : list, storekeys, e-03, ⊦ sks + sk ' + sks0 ≠ []])]]