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Proof step 253 from proof hasSharing-put-index-refval (previous step)

st[r -- sks0] = refval(r1), st[r -- _type] .type = mkarraytype(ty), (st[r -- i ', refval(r4)][r4 -- ((sks3 + i ' ' + sks4) + i ' ' + sks1)]) = refval(r1), st[r4 -- (sks3 + i ' ' + sks4)] = refval(r), (st[r -- i ', refval(r4)][r4 -- (sks3 + i ' ' + sks4)]) = refval(r0), st[r4 -- sks3] = refval(r), 0 < st[r -- _length] .intval, 0 ≤ i, i < st[r -- _length] .intval, fits(r, sks0, st), validref(str, r4, ty, st), disjoint(str, r ' + r4 ', st), fits(r4, sks3 + i ' ' + sks4, st[r -- i ', refval(r4)]), fits(r0, i ' ' + sks1, st[r -- i ', refval(r4)]) ⊦ sks0 = [], r1 = jvmref, r = r4, r = jvmref, sks0 = i ' ' + (sks3 + i ' ' + sks4) + i ' ' + sks1, r4 = jvmref, hasSharing(r, st), hasSharing(r4, st), junkref(str, r, st), ∃ sks2, sks1. sks0 = sks2 + i ' ' + sks1 ∧ st[r -- sks2] .refval = r ∧ (∀ sks. sks + i ' ' ⊑ sks2 → st[r -- sks] .refval ≠ r), ∃ sks2. ¬ (sks2 + i ' ' ⊑ sks3 + i ' ' + sks4 → st[r4 -- sks2] .refval ≠ r), ∃ sks2. ¬ (sks2 + i ' ' ⊑ sks3 → st[r4 -- sks2] .refval ≠ r)

User applied rule exists right

And closed the goal!

Rule argument

[EXRARG : pos: right 11, [extquanttermlist: (sks3)abort:F, discard:T, computed:F]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : list-last, storekeys, app-01-02, ⊦ sks + sks0 ⊑ sks + sks1 ↔ sks0 ⊑ sks1], [CSIMPNAMEDSEQ : list-last, storekeys, prefix-one, ⊦ sk ' ⊑ sk0 ' + sks ↔ sk = sk0], [CSIMPNAMEDSEQ : list, storekeys, a, ⊦ (sks + sks0) + sks1 = sks + sks0 + sks1], [CSIMPNAMEDSEQ : javavalue, , sel-09, ⊦ refval(r) .refval = r])], [EXTRATERMS : (sks3)]]