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Proof step 255 from proof hasSharing-put-index-refval (previous step)

(st[st[r4 -- sks3] .refval -- i ', refval(r4)][r4 -- (sks3 + i ' ' + sks4)]) = refval(r0), st[r4 -- (sks3 + i ' ' + sks4)] = refval(st[r4 -- sks3] .refval), (st[st[r4 -- sks3] .refval -- i ', refval(r4)][r4 -- ((sks3 + i ' ' + sks4) + i ' ' + sks1)]) = refval(r1), st[st[r4 -- sks3] .refval -- _type] .type = mkarraytype(ty), st[st[r4 -- sks3] .refval -- sks0] = refval(r1), fits(r0, i ' ' + sks1, st[st[r4 -- sks3] .refval -- i ', refval(r4)]), fits(r4, sks3 + i ' ' + sks4, st[st[r4 -- sks3] .refval -- i ', refval(r4)]), disjoint(str, st[r4 -- sks3] .refval ' + r4 ', st), validref(str, r4, ty, st), fits(st[r4 -- sks3] .refval, sks0, st), i < st[st[r4 -- sks3] .refval -- _length] .intval, 0 ≤ i, 0 < st[st[r4 -- sks3] .refval -- _length] .intval ⊦ r4 = jvmref, sks0 = i ' ' + (sks3 + i ' ' + sks4) + i ' ' + sks1, st[r4 -- sks3] .refval = jvmref, st[r4 -- sks3] .refval = r4, r1 = jvmref, sks0 = [], junkref(str, st[r4 -- sks3] .refval, st), hasSharing(r4, st), hasSharing(st[r4 -- sks3] .refval, st), ∃ sks2. ¬ (sks2 + i ' ' ⊑ sks3 → st[r4 -- sks2] .refval ≠ st[r4 -- sks3] .refval), ∃ sks2. ¬ (sks2 + i ' ' ⊑ sks3 + i ' ' + sks4 → st[r4 -- sks2] .refval ≠ st[r4 -- sks3] .refval), ∃ sks2, sks1. sks0 = sks2 + i ' ' + sks1 ∧ st[st[r4 -- sks3] .refval -- sks2] .refval = st[r4 -- sks3] .refval ∧ (∀ sks. sks + i ' ' ⊑ sks2 → st[st[r4 -- sks3] .refval -- sks] .refval ≠ st[r4 -- sks3] .refval)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 254:
st[r4 -- sks3] = refval(r) ∧ is_referencevalue(st[r4 -- sks3]), (st[r -- i ', refval(r4)][r4 -- (sks3 + i ' ' + sks4)]) = refval(r0), st[r4 -- (sks3 + i ' ' + sks4)] = refval(r), (st[r -- i ', refval(r4)][r4 -- ((sks3 + i ' ' + sks4) + i ' ' + sks1)]) = refval(r1), st[r -- _type] .type = mkarraytype(ty), st[r -- sks0] = refval(r1), fits(r0, i ' ' + sks1, st[r -- i ', refval(r4)]), fits(r4, sks3 + i ' ' + sks4, st[r -- i ', refval(r4)]), disjoint(str, r ' + r4 ', st), validref(str, r4, ty, st), fits(r, sks0, st), i < st[r -- _length] .intval, 0 ≤ i, 0 < st[r -- _length] .intval ⊦ r4 = jvmref, sks0 = i ' ' + (sks3 + i ' ' + sks4) + i ' ' + sks1, r = jvmref, r = r4, r1 = jvmref, sks0 = [], junkref(str, r, st), hasSharing(r4, st), hasSharing(r, st), ∃ sks2. ¬ (sks2 + i ' ' ⊑ sks3 → st[r4 -- sks2] .refval ≠ r), ∃ sks2. ¬ (sks2 + i ' ' ⊑ sks3 + i ' ' + sks4 → st[r4 -- sks2] .refval ≠ r), ∃ sks2, sks1. sks0 = sks2 + i ' ' + sks1 ∧ st[r -- sks2] .refval = r ∧ (∀ sks. sks + i ' ' ⊑ sks2 → st[r -- sks] .refval ≠ r)

Rule argument

[x0lemmaarg: spec-name: javavalue instance-name: lemma-name: elim-refval antecedent: is_referencevalue(val) succedent: r = val .refval ↔ val = refval(r) substlist: [val, r] → [st[r4 -- sks3], r] add preconditions?: F is rewrite lemma?: F current spec?: F rotate lemma?: T replace all?: T paths: () dummy: () ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : valuefuns, , refval-xtra, ⊦ ¬ is_referencevalue(val) → val .refval = jvmref], [CSIMPELIM : is_referencevalue(val) ⊦ r = val .refval ↔ val = refval(r)])], [EXTRATERMS : (st[r4 -- sks3], r)]]