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Proof step 259 from proof hasSharing-put-index-refval (previous step)

(st[r -- i ', refval(r4)][r4 -- (sks3 + (i ' ' + sks2) + i ' ' + sks1)]) = refval(r1), st[r4 -- (sks3 + i ' ' + sks2)] = refval(r), (st[r -- i ', refval(r4)][r4 -- (sks3 + i ' ' + sks2)]) = refval(r0), (st[r -- i ', refval(r4)][r0 -- i ']) = refval(r2), st[r -- sks0] = refval(r1), st[r -- _type] .type = mkarraytype(ty), st[r4 -- sks3] = refval(r), 0 < st[r -- _length] .intval, fits(r4, sks3 + i ' ' + sks2, st), fits(r2, sks1, st[r -- i ', refval(r4)]), 0 ≤ i, i < st[r -- _length] .intval, fits(r, sks0, st), validref(str, r4, ty, st), disjoint(str, r ' + r4 ', st), ∀ sks. sks + i ' ' ⊑ sks3 → st[r4 -- sks] .refval ≠ r, is_arraytype(st[r0 -- _type] .type) → i < st[r0 -- _length] .intval ⊦ sks0 = i ' ' + sks3 + (i ' ' + sks2) + i ' ' + sks1, r4 = jvmref, r0 = jvmref, sks0 = [], r1 = jvmref, r = r4, r = jvmref, hasSharing(r, st), hasSharing(r4, st), junkref(str, r, st), is_classtype(st[r0 -- _type] .type), ∃ sks. ¬ (sks + i ' ' ⊑ sks3 + i ' ' + sks2 → st[r4 -- sks] .refval ≠ r), ∃ sks, sks4. sks3 + i ' ' + sks2 = sks + i ' ' + sks4 ∧ st[r4 -- sks] .refval = r ∧ (∀ sks2. sks2 + i ' ' ⊑ sks → st[r4 -- sks2] .refval ≠ st[r4 -- sks] .refval), ∃ sks2, sks1. sks0 = sks2 + i ' ' + sks1 ∧ st[r -- sks2] .refval = r ∧ (∀ sks. sks + i ' ' ⊑ sks2 → st[r -- sks] .refval ≠ r)

User applied rule exists right

And closed the goal!

Rule argument

[EXRARG : pos: right 12, [extquanttermlist: (sks3)abort:F, discard:T, computed:F]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : list-last, storekeys, app-01-02, ⊦ sks + sks0 ⊑ sks + sks1 ↔ sks0 ⊑ sks1], [CSIMPNAMEDSEQ : list-last, storekeys, prefix-one, ⊦ sk ' ⊑ sk0 ' + sks ↔ sk = sk0], [CSIMPNAMEDSEQ : list, storekeys, a, ⊦ (sks + sks0) + sks1 = sks + sks0 + sks1], [CSIMPNAMEDSEQ : javavalue, , sel-09, ⊦ refval(r) .refval = r])], [EXTRATERMS : (sks3)]]