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Proof step 294 from proof hasSharing-put-index-refval (previous step)

¬ ¬ (∃ sks0, sks1. sks3 = sks0 + (i ' + sks1) ∧ st[r4 -- sks0] .refval = r0 ∧ (∀ sks2. sks2 + i ' ⊑ sks0 → st[r4 -- sks2] .refval ≠ r0)), st[r0 -- sks0] = refval(r1), st[r0 -- _type] .type = mkarraytype(ty), (st[r0 -- i ', refval(r4)][r4 -- sks3]) = refval(r1), 0 < st[r0 -- _length] .intval, 0 ≤ i, i < st[r0 -- _length] .intval, fits(r0, sks0, st), validref(str, r4, ty, st), disjoint(str, r0 ' + r4 ', st), fits(r4, sks3, st) ⊦ sks0 = [], r1 = jvmref, r0 = r4, r0 = jvmref, sks0 = i ' ' + sks3, sks3 = [], r4 = jvmref, hasSharing(r0, st), hasSharing(r4, st), junkref(str, r0, st), ∃ sks, sks1. sks0 = sks + i ' ' + sks1 ∧ st[r0 -- sks] .refval = r0 ∧ (∀ sks2. sks2 + i ' ' ⊑ sks → st[r0 -- sks2] .refval ≠ r0), ∃ sks, sks1. sks3 = sks + i ' ' + sks1 ∧ st[r4 -- sks] .refval = r0 ∧ (∀ sks2. sks2 + i ' ' ⊑ sks → st[r4 -- sks2] .refval ≠ st[r4 -- sks] .refval)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 293:
st[st[r4 -- sks1] .refval -- sks0] = refval(r1), st[st[r4 -- sks1] .refval -- _type] .type = mkarraytype(ty), (st[st[r4 -- sks1] .refval -- i ', refval(r4)][r4 -- (sks1 + i ' ' + sks)]) = refval(r1), 0 ≤ i, i < st[st[r4 -- sks1] .refval -- _length] .intval, fits(st[r4 -- sks1] .refval, sks0, st), validref(str, r4, ty, st), disjoint(str, st[r4 -- sks1] .refval ' + r4 ', st), fits(r4, sks1 + i ' ' + sks, st), 0 < st[st[r4 -- sks1] .refval -- _length] .intval, ∀ sks2. sks2 + i ' ' ⊑ sks1 → st[r4 -- sks2] .refval ≠ st[r4 -- sks1] .refval ⊦ r4 = jvmref, sks0 = [], r1 = jvmref, st[r4 -- sks1] .refval = r4, st[r4 -- sks1] .refval = jvmref, sks0 = i ' ' + sks1 + i ' ' + sks, hasSharing(st[r4 -- sks1] .refval, st), hasSharing(r4, st), junkref(str, st[r4 -- sks1] .refval, st), ∃ sks, sks2. sks0 = sks + i ' ' + sks2 ∧ st[st[r4 -- sks1] .refval -- sks] .refval = st[r4 -- sks1] .refval ∧ (∀ sks2. sks2 + i ' ' ⊑ sks → st[st[r4 -- sks1] .refval -- sks2] .refval ≠ st[r4 -- sks1] .refval), ∃ sks2, sks3. sks1 + i ' ' + sks = sks2 + i ' ' + sks3 ∧ st[r4 -- sks2] .refval = st[r4 -- sks1] .refval ∧ (∀ sks. sks + i ' ' ⊑ sks2 → st[r4 -- sks] .refval ≠ st[r4 -- sks2] .refval)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDFORWARD : int-abs, , forward-le-05, ⊦ i < j ∧ 0 ≤ i → 0 < j], [CSIMPNAMEDSEQ : list, storekeys, Last, ⊦ sks + sk = sks + sk '], [CSIMPNAMEDSEQ : list, storekeys, a, ⊦ (sks + sks0) + sks1 = sks + sks0 + sks1], [CSIMPNAMEDSEQ : list, storekeys, e-03, ⊦ sks + sk ' + sks0 ≠ []], [CSIMPNAMEDSEQ : list, storekeys, c, ⊦ sk + sks = sk ' + sks])]]